Question

Help with equations, please?

Answer 1

shoot me

Answer 2

Amanda tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value for x that makes the denominator zero, and you can't divide by zero," Amanda explains. Using complete sentences, demonstrate to Amanda how the equation is still solvable.

Answer 3

@Loser66

Answer 4

@iambatman

Answer 5

consider \(f(x)=\dfrac{x^2-1}{x-1}\)

Answer 6

it is solvable, right?

Answer 7

Yes!

Answer 8

But how does that apply to this problem?