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Mathematics 12 Online
OpenStudy (anonymous):

Choose an employee person at random. Let A be the event that the person is a female and B be the event that the person holds a managerial position. Data from the US department of labor suggests that P(A)= 0.47 and P(B|A)= 0.34 A) explain what P(A)= 0.47 means in context B) explain what P(B|A)= 0.34 means in context C) what is the probability that a randomly chosen employed person is a male? D) what is the probability that a randomly chosen employed person is a female manager? E) what is the probability that a randomly chosen employed female is not a manager?

OpenStudy (anonymous):

I have this so far a. The probability of choosing a female is 49% b. what is the probability of getting a female if we know we are getting a person who holds a managerial position

OpenStudy (anonymous):

i need help with the rest

OpenStudy (anonymous):

@MathHelpp10x

OpenStudy (anonymous):

did anyone get this?

OpenStudy (anonymous):

A. This means that the female population is 47% That also means that Population of men is 53% B. probability of a female manager is 34% C. 53% of the population is male D. 34% is female manager E. 66% chance the female is not a manager.

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