Question

Identify a quadratic function that fits the points (−1, 8),(2, −1), and (3, 0).

Answer 1

you can use the standard form of a quadratic y = ax^2 + bx + c

Plug in the points given, you will have a system of three equations in three unknowns

For example if we plug in (-1,8) we get

8 = a *(-1)^2 +b(-1) + c

Answer 2

which simplifies to
8 = a - b + c

Answer 3

oh okies and what do i do next?

Answer 4

plug in the other two points

Answer 5

plug (2,-1) into
y = ax^2 + bx + c

-1 = a(2)^2 + b(2) + c

this simplifies to
-1 = 4a + 2b + c

Answer 6

f(x)= x^2-4x+3

Answer 7

yes that looks right, how did you get that?

Answer 8

this online calculator :D

Answer 9

do you have a link ?

Answer 10

sure I do http://www.softschools.com/math/algebra/quadratic_functions/quadratic_function_with_three_points/

Answer 11

you can also solve it using TI-84