Question

Let g be the function defined by g(x)=-x^2+2x g((squareroot)a),

Answer 1

try to substitute
\[\sqrt{a}\]
inplace of x

Answer 2

oops...in place of x

Answer 3

hint:
\[g(\sqrt{a})=-[(\sqrt{a})^{2}]+2\sqrt{a}=...\]
please continue

Answer 4

YEah I got that part down but not sure how to solve after @Michele_Laino

Answer 5

please note that:
\[(\sqrt{a})^{2}=a\]

Answer 6

so, you should get this:
\[g(\sqrt{a})=-a+2\sqrt{a}\]

Answer 7

Great thank you! @Michele_Laino I did not realize that (Sqareroot)a ^2 is = to a

Answer 8

thank you!