(HELP PLEASE) If a line passes through point (-1,2) and has slope m=a/b for a>0 and b>0, then which of the following points must lie of the graph of this line? A. (-1-a,2-b) B. (-1+b,2-a) C. (-1+b,2+a) D.(-1+a,2+b) I think it be between D or B. Im not sure really.
What is the equation of a line?
y=mx+b?
yup, and you are given slope m = a/b, then y =?
oh, you confused , me too. Ok, this b is not the b in m = a/b,
I change a little bit: y = mx + h, ok?
then y=a/bx+h?
m = a/b, hence \(y = \dfrac{a}{b}x +h\)
yup, now find h
do you know how?
no...
you are given the point (-1, 2) that is x =-1, y =2, just plug it into y above.
\(h = y-\dfrac{a}{b}x\) replace the values of x and y to get h
this is like extremely hard
so?? if you have another way, please help us. I know this way only :)
I got it its C.
yup, me too
The point (-1,2) is on this line the slope is m = a/b, so slope = rise/run = a/b rise = a run = b therefore you start at (-1,2) and go up 'a' units and go to the right 'b' units. You'll go from (-1,2) to (-1+b, 2+a) |dw:1422752618532:dw|
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