Question

f(x) = 3sin(2x), my amplitude is 3, is my period 2?

Answer 1

\[\huge\rm y = A \sin (B \theta-C )+ D\]
here a is amplitude and
period should be 2pi/B

Answer 2

the amplitude should be |A| to make sure it's never negative

Answer 3

yeah amplitude never going to be negative ;)

Answer 4

the period is found using this \[2x=2\pi \Longrightarrow x=\pi\]

Answer 5

so the period is pi

Answer 6

yes

Answer 7

APPLE pi

Answer 8

hahaha :)

Answer 9

the period in general is obtained by:
\[period=\frac{2\pi}{|B|}\]

Answer 10

i drew a graph of the function and put the period as 2 pi and it was marked right, now I am totally confused :(