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given f(x) = 3sin(2x) and g(x) = 3/2. evaluate algebraically the points where the 2 functions intercept domain of [0.2pi],
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does this really mean solve \[3\sin(2x)=\frac{3}{2}\]
if so, then \[\sin(2x)=\frac{1}{2}\] which is easy enough to solve for \(2x\) then divide by 2 to get \(x\)
that is what I did, is that correct?
did you get \(2x=\frac{\pi}{6}\)?
also \[2x=\frac{5\pi}{6}\]
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yes :) my next two I got 13pi/12 and 17pi/12
looks reasonable
cool, thank you :)
yw
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