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Mathematics 16 Online
OpenStudy (anonymous):

hlp

OpenStudy (anonymous):

@DanJS

OpenStudy (snowsurf):

The formula for volume of a sphere is \[V = \frac{ 4 }{ 3 }\pi r^{3}\] In this problem you are given the diameter bur volume of a sphere require a radius. d=2r. That means a diameter is twice the length of a a radius. r = d/2. Once you find what r is then plug that into the volume of a sphere and you will get your answer.

OpenStudy (sleepyjess):

@snowsurf gave you the formula for volume of a sphere. I know you said that you don't get it, what do you not get?

OpenStudy (anonymous):

how to plug it in

OpenStudy (sleepyjess):

the diameter is r*2, so to get r, you need to do d/2

OpenStudy (anonymous):

so 18/2

OpenStudy (sleepyjess):

yes

OpenStudy (sleepyjess):

so r = 9, now put 9 into the formula in place of r

OpenStudy (anonymous):

18/2^9

OpenStudy (sleepyjess):

18/2^9???

OpenStudy (anonymous):

idk

OpenStudy (sleepyjess):

what is 18/2?

OpenStudy (anonymous):

6

OpenStudy (sleepyjess):

how do you get 6?

OpenStudy (anonymous):

srry 9

OpenStudy (snowsurf):

Okay. r =9 like you got.

OpenStudy (snowsurf):

Now you can plug that into the volume of a sphere I gave you

OpenStudy (anonymous):

thx u to both of yall I gave both of yall a medal this is to hard and I hve no clue wht so ever how to plug in the numbers

OpenStudy (snowsurf):

So \[r =9\] the volume of a sphere is \[V = \frac{ 4 }{ 3 }\pi r ^{3} \] Since you know the radius is 9 you can substitute that into the formula.\[V=\frac{ 4 }{ 3 }\pi 9^{3}\] The rest just simplifying the result.

OpenStudy (anonymous):

can send e an online calcutor

OpenStudy (anonymous):

3053.63 in^3

OpenStudy (snowsurf):

That is the correct answer.

OpenStudy (anonymous):

they send they want want exact so

OpenStudy (snowsurf):

To get the exact don't compute pi with it.

OpenStudy (anonymous):

yes maybe round o something like tht

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