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Mathematics 6 Online
OpenStudy (anonymous):

More medals :D: http://gyazo.com/2a7fee63324c5c01be9d58ae611cbfd1

OpenStudy (anonymous):

@Chop-GTA5

OpenStudy (anonymous):

I dont know this one sorry

OpenStudy (anonymous):

No problem. :)

OpenStudy (snowsurf):

In the problem is PQ perpendicular to RS?

OpenStudy (anonymous):

I am not fully sure.

OpenStudy (triciaal):

Look at right- triangle PQS use pythagorean theorem to find QS Cos PSQ = A/H = QS/PS similar figures Cos PSQ = RS/(2PS) remember P is the center of circle so diameter = 2PS use substitution 2QS = square root of (ps^2 - pq^2 so I got D

OpenStudy (anonymous):

Ohhh, alright thank you @triciaal . I have more questions i'll be posting soon.

OpenStudy (triciaal):

open new questions

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