Question

More medals :D:

http://gyazo.com/2a7fee63324c5c01be9d58ae611cbfd1

Answer 1

@Chop-GTA5

Answer 2

I dont know this one sorry

Answer 3

No problem. :)

Answer 4

In the problem is PQ perpendicular to RS?

Answer 5

I am not fully sure.

Answer 6

Look at right- triangle PQS
use pythagorean theorem to find QS
Cos PSQ = A/H = QS/PS
similar figures
Cos PSQ = RS/(2PS) remember P is the center of circle so diameter = 2PS
use substitution
2QS = square root of (ps^2 - pq^2
so I got D

Answer 7

Ohhh, alright thank you @triciaal . I have more questions i'll be posting soon.

Answer 8

open new questions