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Physics 18 Online
OpenStudy (anonymous):

A hare and a tortoise compete in a race over a straight course 2.50 km long. The tortoise crawls at a speed of 0.230 m/s toward the finish line. The hare runs at a speed of 9.00 m/s toward the finish line for 2.000 km and then stops to tease the slow-moving tortoise as the tortoise eventually passes by. The hare waits for a while after the tortoise passes and then runs toward the finish line again at 9.00 m/s. Both the hare and the tortoise cross the finish line at the exact same instant. Assume both animals, when moving, move steadily at their respective speeds.

OpenStudy (compphysgeek):

and the question?

OpenStudy (anonymous):

(a) How far is the tortoise from the finish line when the hare resumes the race?

OpenStudy (anonymous):

(b) For how long in time was the hare stationary?

OpenStudy (compphysgeek):

you can first calculate the times the hare and the tortoise need to run the last 500 metres. As v = s/t you can solve the equation for t. the difference will tell you then how long the hare waited and you can calculate the distance the tortoise moved in that time

OpenStudy (anonymous):

Thanks so much!!

OpenStudy (compphysgeek):

no worries. let's check if we got the same numbers

OpenStudy (anonymous):

Honestly it will take me hours to possibly get to an accurate answer. But I will try. This is my first Physics class and I'm having an extraordinary time actually understanding it.

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