Question

Amber measured the length of her yard by walking from one end of the yard to the other. She counted 44 steps. Assuming that each of her steps was m in length, Amber said the length of her yard was m. The actual length of her yard is 19 m.

What was the percent error in Amber’s measurement? Round to the nearest tenth of a percent, if necessary.

A.
13.6%

B.
15.8%

C.
76%

D.
131.6%

Answer 1

Your missing where is says m in length.

Answer 2

its1/2 sorry

Answer 3

@Jhannybean please help :)

Answer 4

@TheSmartOne

Answer 5

im missing a length XD

Answer 6

Amber measured the length of her yard by walking from one end of the yard to the other. She counted 44 steps. Assuming that each of her steps was 1/2 m in length, Amber said the length of her yard was22 m. The actual length of her yard is 19 m.

What was the percent error in Amber’s measurement? Round to the nearest tenth of a percent, if necessary.

A.
13.6%

B.
15.8%

C.
76%

D.
131.6%

Answer 7

So each of her steps was 1/2 m. And she took 44 steps. How much is the length of the distance she walked?

Answer 8

22 m

Answer 9

Correct.

And the actual distance was 19 m.

Answer 10

yeah

Answer 11

And do you know the percent error formula?

Answer 12

@morganlauren11

Answer 13

|22m-19m| / 19m

Answer 14

x 100

Answer 15

@TheSmartOne

Answer 16

percent error \[ = \frac{ (\left| Actual - measurment \right|) }{ Actual } 100%\]

Answer 17

Correct @morganlauren11

Answer 18

i know how how to do it and i get 30%

Answer 19

You should put absolute values because you can get negative numbers. In this case it does not but in some cases you can.

Answer 20

i did that

Answer 21

Ok @morganlauren11 lets do it step by step

Answer 22

What is 22-19=?

Answer 23

3

Answer 24

Ok now what is