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If b(g(x)) = 5x^2 - 13, find b(x). Given that g(x)= x^2 - 2.
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I got so far as to realize: \[5x ^{2}-13 = b(x ^{2}-2)\] I just don't know how to isolate b(x)
@phi
this seems like a hard problem. b(x) is a function and the idea is if we replace x with a complicated "x" (i.e. x^2-2) we will get out 5x^2-13 because we have x^2 in the answer, I would start by guessing b(x) = x then b(x^2-2) gives x^2 -2 and that does not match 5x^2-13 maybe if we multiply by 5 in our guess? b(x) = 5x what do we get for b(x^2-2) now ?
i'm still lost
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