Question

3(x-5)^1/3 = -9
the answer is {-22}
needs to show the work, and dont know how to get there;

Answer 1

first isolate the (x-5)^(1/3) by undoing the multiplication there by 3
to undo that multiplication by 3 you will have to divide both sides by 3
that is do:
\[\frac{3(x-5)^\frac{1}{3}}{3}=\frac{-9}{3} \\ \frac{3}{3}(x-5)^\frac{1}{3}=\frac{-9}{3}\]
I will let you finish this step

Answer 2

are you there?

Answer 3

step by step:

Answer 4

3(x-5)^1/3 = -9 (divide both sides by 3) (-9/3=-3)
(x-5)^1/3 = -3 (raise both sides to exponent 3 to ger riid of cube root 1/3)
[(x-5)^1/3]^3 = (-3)^3 (exponent 3 cancels exponent 1/3 since 3/3=1)
(x-5) = -27 (take -5 to other side)
x = -22