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Mathematics 21 Online
OpenStudy (anonymous):

What is the solution to the system of equations? http://static.k12.com/bank_packages/files/media/mathml_d676641518b9981930709d538c634ae09a39918d_1.gif (______,_____)

OpenStudy (mkapad01):

make one of the equations equal to a variable, maybe y, and then plug that into the other equation

OpenStudy (anonymous):

So, if i were to plug it in it would look like this x - 2( -3 + 2x) = -4, Right?

OpenStudy (mkapad01):

it would be minus 2x

OpenStudy (anonymous):

oh ya right.

OpenStudy (mkapad01):

yah, besides that, that's correct, just solve for x

OpenStudy (mkapad01):

after you get x, plug that into the other equation

OpenStudy (anonymous):

Then when i solve it i'd get -2x(6+0) = -4

OpenStudy (anonymous):

An then -12x - 2 = -4 -14x = -4

OpenStudy (anonymous):

wait not -14x 14

OpenStudy (anonymous):

14x*

OpenStudy (anonymous):

i got -3.5

OpenStudy (mkapad01):

|dw:1422838238307:dw|

OpenStudy (anonymous):

?

OpenStudy (anonymous):

So then i plug in -2 into x - 2y = -4 Which would look like this: -2 - 2y - -4

OpenStudy (mkapad01):

yup

OpenStudy (anonymous):

y = 6

OpenStudy (anonymous):

y = -6*

OpenStudy (anonymous):

( -2, -6) ?

OpenStudy (mkapad01):

|dw:1422838593996:dw|

OpenStudy (anonymous):

oops i put the 2 by the y to the left so (-2, 1) corret?

OpenStudy (anonymous):

I mean to the right.

OpenStudy (mkapad01):

oh, :) it okay

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