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The slope of the tangent line to a curve at any point (x, y) on the curve is x/y. What is the equation of the curve if (3, 1) is a point on the curve?
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the slope is \(\frac{x}{y}\)?
yes
i think that means \[y'=\frac{x}{y}\] right?
That's what i'm thinking
in other words this is the unit circle
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I guess so
ah dang i am wrong, if it was the unit circle then it would be \[y'=-\frac{x}{y}\]
this one is "separable"
y ' = x/y dy/dx = x/y y*dy = x*dx integrate both sides to get (y^2)/2 = (x^2)/2 + C
hopefully you see what to do from here
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Ohh I think i see know. Give me a second
are you able to determine the value of C?
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