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Mathematics 8 Online
OpenStudy (anonymous):

The degree of the polynomial function represented by the graph is ( ), and it's leading coefficient is ( ).

OpenStudy (anonymous):

OpenStudy (7thgrader):

you mind changing your pic?

OpenStudy (7thgrader):

and also are there any abcd?

OpenStudy (anonymous):

If I must? Is there something wrong with it? There are no abcd it just gives me the picture.

OpenStudy (7thgrader):

hhhmmmmm do you have any idea?

OpenStudy (7thgrader):

what grade math is this?

OpenStudy (anonymous):

12th alegabra 2. I have no idea where to start.

OpenStudy (7thgrader):

http://www.purplemath.com/modules/polyends.htm

OpenStudy (7thgrader):

i hope this helped like my username says im only in 7th grade

OpenStudy (anonymous):

From that I can see that my leading coefficient is going to be negative.

OpenStudy (7thgrader):

@ganeshie8 @DarkMoonZ @AnswerMyQuestions

OpenStudy (anonymous):

Thank you @7thGrader.

OpenStudy (7thgrader):

@Mr.Man420

OpenStudy (anonymous):

Bahahaha.

OpenStudy (7thgrader):

have a nice day

OpenStudy (anonymous):

You too.

OpenStudy (7thgrader):

and about your pic you should make more interesting like maybe the both of you take a selfie at a like or something make it more bright and happ this one looks like the start of a porn movie sorry to break it to you

OpenStudy (7thgrader):

*lake not like

OpenStudy (anonymous):

Good idea!!

OpenStudy (7thgrader):

do you do online school?

OpenStudy (anonymous):

Technically im finishing my last credit on plato. Then I'm a highschool graduated. Way late ,but better then never.

OpenStudy (anonymous):

Graduate*

OpenStudy (anonymous):

@iGreen.

OpenStudy (anonymous):

@shrutipande9 @SithsAndGiggles @paki

OpenStudy (anonymous):

@paki

OpenStudy (paki):

@YanaSidlinskiy help please...

OpenStudy (yanasidlinskiy):

Someone has provided you with a link. That should help! Leading term is _____ and the function is represented by the _______...It's kind of like fill in the blank. If you've taken a look at the website that has been provided, you should get your answer. It's pretty straight forward.

OpenStudy (anonymous):

ok.

OpenStudy (yanasidlinskiy):

And I don't see how you wouldn't get the answer. It's a straight forward link.

OpenStudy (anonymous):

I just realized there was more than one page to the link.

OpenStudy (yanasidlinskiy):

What do you mean?

OpenStudy (anonymous):

Yana I read all that, from it It I didn't get much. If you had never done a problem like this, could you accomplish it with just the link and knowone to explain it to you?

OpenStudy (anonymous):

@YanaSidlinskiy Could you check what I have? The degree of the polynomial function represented by the graph is (even), and the leading coefficient is (positive).

OpenStudy (anonymous):

@Data_LG2 Do you know if i'm right or wrong?

OpenStudy (anonymous):

@mathmath333 Am I right that the degree of the polynomial function represented by the graph is (even), and the leading coefficient is (positive)?

OpenStudy (anonymous):

OpenStudy (anonymous):

That's what I thought at first, but I changed it for some reason. Thank you @Data_LG2.

OpenStudy (anonymous):

just remember the parent function to know whether it is even (quadratic, quartic) or odd (cubic, quintic) ... based the functions' behaviours from the parent functions' graph to determine the sign of the leading coefficient.

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