Question

Please help!

Graph the circle with center at (3, -2), which also passes through the point (0, 2). Label the
center and at least four points on the circle. Write the equation of the circle.

Answer 1

Please don't tag everyone in your question.

Answer 2

Please help

Answer 3

umm well have you ever used a program called geogebra because it might help
because to tell you the truth I can help you on this sorry

Answer 4

@k_lynn

Answer 5

@Quan99

Answer 6

you can draw the graph manually by plotting the points (3,-2) the center and the point (0,2)

Answer 7

then using a compass place the point of the compass at the center and draw a circle through the other point.

Answer 8

this might help I graphed it and I put 4 points on the circle

Answer 9

the distance between the 2 points is the radius of the circle and the equation of the circle will be
(x -a )^2 + (y - b)^2 = r^2

where (a , b) is the center (3, -2) and r is the radius you have measured

Answer 10

@lexie<3 - the center is (3 , -2) not (-3,-2)

Answer 11

oh soorrrryyyyy

Answer 12

use the diatance formula to find \(r\)

Answer 13

\(\large \begin{align} \color{black}{r=\sqrt{(3-0)^2+(-2-2)^2} \hspace{.33em}\\~\\
}\end{align}\)

Answer 14

would that be it? @cwrw238