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Exponent question
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|dw:1422921447365:dw|
Recall \[\sqrt[n]{x} = x^{1/n}\]
Using that rule, you can rewrite the thing as... \[\frac{ 9^{1/4} *9^{1/2} }{ 9^{5/4} }\]
Now use the exponent rule... \[x^a*x^b = x^{a+b}\] and \[\frac{ 1 }{ x^a } = \frac{ x^{-a} }{ 1 }\]
so what's the question exactly? you don't know how to solve this?
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so then it would be 9^3/4-9 ^5/4
So 9^-1/2 Thank you so much c:
careful when you type in exponents, use parenthesis. 9^(3/4) for example
You are right so far. you can simplify more still
\[9^{-1/2}=\frac{ 1 }{ 9^{1/2} } = \frac{ 1 }{ \sqrt{9} } = \frac{ 1 }{ 3 }\]
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