in the following triangle, theta= 60. find the values of the angles B and B', which solve this ambiguous case
@triciaal @DanJS
@jim_thompson5910
@Directrix
ANYONE? GETS A MEDAL AND LOTS OF THANKS
Since the smaller triangle has equal length legs, the two angles opposite those legs are equal... So you can form a straight line with B and B' B + B' = 180
so the two that add up 180? will be? @DanJS
you can use the law of sines or cosines to figure out what B' will be. Have you gone over those yet?
YEAH, I still get confused
|dw:1422923802485:dw|
\[\frac{ \sin(60) }{ 12.3 } = \frac{ \sin(B ') }{ 13 }\]
cross multiply?
That will give you B ' THen use the fact that B + B ' = 180 , to get B
31.96?
148.04? @DanJS
I got 113.75 and 66.25 for the pair
When you solve, you get 66.25, recall from symmetry of the unit circle, that the sin of the angle is the Y coordinate, ...like this
|dw:1422924695665:dw|
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