Question

u substitution integral

Answer 1

http://www.wolframalpha.com/input/?i=integral+from+0+to+pi%2F2+sin%28x%29%281-cos%5E2%28x%29%29dx

Answer 2

here is wolfram alpha with the answer but Im not getting that when I do it

Answer 3

here is my method\[\int\limits_{0}^{\pi/2} \sin(x)(1-\cos^{2}(x))^{2}\]
u=cos(x) du=-sin(x)dx

Answer 4

\[-\int\limits (1-u^{2})^{2}du\]

Answer 5

\[-\int\limits u^{4}-2u^{2}+1du\]

Answer 6

what is your integral?

Answer 7

the original integral is the one in the third response

Answer 8

but the one you put in wolfram is different did you realize that?!

Answer 9

you were missing square that's probably why you are getting a wrong answer

Answer 10

your sub is good

Answer 11

thank you were right sorry about that

Answer 12

http://www.wolframalpha.com/input/?i=integral+from+0+to+pi%2F2+sin%28x%29%281-cos%5E2%28x%29%29%5E2dx

Answer 13

this is the result you should get