Question

Last one
Simplify completely the quantity 14 times x to the 5th power times y to the 4th power plus 21 times x to the third power times y to the 2nd power all over 7 times x to the third power times y.

2x8y5 + 3x6y3
2x2y4 + 3xy
2x2y3 + 3y
2x2y3 + 3y2

Answer 1

@iGreen.

Answer 2

\(\dfrac{14x^5y^4 + 21x^3y^2}{7x^3y}\)

Divide \(7x^3y\) to the first term:

\(14x^5y^4 \div 7x^3y \rightarrow \dfrac{14}{7}x^{5-3}y^{4-1}\)

Can you simplify that? Just divide 14/7 and subtract the exponents.

Answer 3

2x^2y3

Answer 4

C is the answer correct?

Answer 5

Yep, C is correct.