Question

http://k12.kitaboo.com/eBookWs/ebook/maths/maths19/# i need help on page 176

Answer 1

you will get a medal and a fan

Answer 2

which Question?

Answer 3

14 and 15

Answer 4

-11 7/13y is 14

Answer 5

thx

Answer 6

3 is 15

Answer 7

14.

\(5 \cdot y \cdot (-2 \dfrac{4}{13} )\)

\( = -5 \cdot y \cdot (2 + \dfrac{4}{13} )\)

\( = -[5y (2 + \dfrac{4}{13} )]\)

\( = -[10y + \dfrac{20}{13}y ]\)

\( = -[10y + 1\dfrac{7}{13}y ]\)

\( = -[11\dfrac{7}{13}y ]\)

\( = -11\dfrac{7}{13}y\)

Answer 8

15.

\(7\dfrac{1}{2} \div 2\dfrac{1}{2}\)

\(= \dfrac{15}{2} \div \dfrac{5}{2} \)

\(= \dfrac{15}{2} \times \dfrac{2}{5} \)

\(= \dfrac{15 \times 2}{2 \times 5} \)

\(= \dfrac{30}{10} \)

\(= 3\)

Answer 9

thank you can you help me more

Answer 10

yes