May I have some help solving inequalities? I will Medal for some assistance with these problems? 3/5=x/5 3+3/4=n/3 I have four more but that's a start.
wait im gonna solve it
I got the first one, the second and so on are far more complex.
what are they?
\[\frac{ 1 }{ 9y-7 } = \frac{ 2 }{ 4y }\]
\[\frac{ 2 }{ x+5 }=\frac{ 1 }{ x+3 }\]
18 y - 14= 4 y 14 y = 14 y = 1
x+ 5 = 2x + 6 x = -1
Buddy, to solve such problems just hit both side by the bottom of the fraction
sides*
this scheme will help you solve any problem of this type
Right on, thanks for the advice.
You are welcome.But if you stuck with a problem don't hesitate to ask for help
I'll message you if need be, my assignment is only six problems long. The last one is confusing the heck out of me though.
I'll just post it now and ask. It asks to solve for y... \[\frac{ x }{ y}=\frac{ a }{ b }\]
ay = b x y = bx/a
In such problem , don't expect to get numbers even if you were a wizard.
Huh, okay right on, thanks man.
yw
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