Question

can someone help me with

evaluate the expressions

(-4/7)^0

and -(5)^0

Answer 1

any number to the power of zero is ONE
so the first one is ONE

Answer 2

the second on is not one, because the minus sign is out front
that makes the second one MINUS ONE

Answer 3

just 1 that's it? so the answer is 1? and how is that possible ?

Answer 4

how is what possible?

Answer 5

im sorry im so dumb at math im trying to learn im just wondering how does (-4/7)^0 turn into 1

Answer 6

\[b^0=1\] always

Answer 7

For example
\[\frac{ 3^2 }{ 3^2 } = 1 = \frac{ 3^{2-2} }{ 1 } = 3^0\]

Answer 8

it is just notation
that is all
don't try to think too hard about it
like "multiply a number by itself zero times" means nothing

Answer 9

it makes the rules of exponents consistent is all, so it is defined that way

Answer 10

ok can you help me with more?

Answer 11

A number divided by itself equals 1, following the exponent rules, you can also say a number to zero power is 1.

Answer 12

k

Answer 13

can you help me with more?

Answer 14

k

Answer 15

evaluate
10^-6

is it -60?

Answer 16

no it is certainly not

Answer 17

\[\huge b^{-n}=\frac{1}{b^n}\]
\[\huge 10^{-6}=\frac{1}{10^6}\]

Answer 18

\[10^6=1,000,000\] so
\[10^{-6}=\frac{1}{1,000,000}\]

Answer 19

so 1/10^6 is the answer? im trying to figure out how to solve it because my books make no since to me

Answer 20

yes, the answer is \(\frac{1}{10^6}\) or \(\frac{1}{1,000,000}\) or \(0.000001\)

Answer 21

ok what about rewrite the expression without using a negative exponent
1/6x^-5
simplify as much as possible

Answer 22

the minus sign in the exponent means the reciprocal
if it is up, bring it down
if it is down, bring it up

Answer 23

\[\frac{1}{6x^{-5}}=\frac{x^5}{6}\]

Answer 24

your awesome! finally something makes since lol I have a few more questions if you don't mind?

Answer 25

go ahead although i have to run soon

Answer 26

write p^2 (p^5) without exponents
and fill in the blank p^2 (p5) =p?

Answer 27

without exponents?

Answer 28

it would just be
\[ppppppp\] seven copies of \(p\)

Answer 29

\[p^2\times p^5=p^{2+5}=p^7\] easier to write with exponents

Answer 30

ok thank you only a few more im sorry for bothering you

Answer 31

x(x^2)(x^2) simplify

Answer 32

\[x^{1+2+2}=x^5\]

Answer 33

multiply
5v(3v^5w^3)2w^8
simplify as much as possible

Answer 34

\[5v(3v^5w^3)2w^8\] not sure what the parentheses are for

Answer 35

multiply the numbers, you get \(30\)

Answer 36

I just put them there because I didn't know what else to put for multiplication

Answer 37

add the exponents you get
\[\large 30v^6w^{11}\]

Answer 38

simplify
v^-3 (v^-9)
write only with positive exponents only