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help!! medal given ! use the figure to find the exact value of each trigonometric function. 2sin a/2 cos a/2
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\[2\sin \frac{ \alpha }{ 2 }\cos \frac{ \alpha }{ 2 }\]
That reminds me of the double angle formula for sine.
the second angle will have the hypotnuse of 25
and yes i agree
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and yes i agree\[\sqrt{\frac{ 1-\cos \alpha }{ 2}}\]
I was just about to ask you about the hypotenuse of that triangle. If you know Pythagorean triples, you'd recognize the 25 right off.
yes
And, did you know that when a hypotenuse and a leg differ by 1, then the mystery leg is the square root of the sum of the hypotenuse and the leg that differs by 1. |dw:1423007448129:dw|
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