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Mathematics 9 Online
OpenStudy (anonymous):

help!! medal given ! use the figure to find the exact value of each trigonometric function. 2sin a/2 cos a/2

OpenStudy (anonymous):

OpenStudy (anonymous):

\[2\sin \frac{ \alpha }{ 2 }\cos \frac{ \alpha }{ 2 }\]

Directrix (directrix):

That reminds me of the double angle formula for sine.

OpenStudy (anonymous):

the second angle will have the hypotnuse of 25

OpenStudy (anonymous):

and yes i agree

OpenStudy (anonymous):

and yes i agree\[\sqrt{\frac{ 1-\cos \alpha }{ 2}}\]

Directrix (directrix):

I was just about to ask you about the hypotenuse of that triangle. If you know Pythagorean triples, you'd recognize the 25 right off.

OpenStudy (anonymous):

yes

Directrix (directrix):

And, did you know that when a hypotenuse and a leg differ by 1, then the mystery leg is the square root of the sum of the hypotenuse and the leg that differs by 1. |dw:1423007448129:dw|

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