Question

Please help!

Use the method of completing the square to

Transform the quadratic equation into the equation form (x – p)2 = q.

-9 + 12x - 6x^2 = 0


A)
(x - 1)2 = -0.5
B)
(x - 1)2 = -1.5
C)
(x - 1)2 = 0.5
D)
(x - 1)2 = 1.5

Answer 1

First.

-9+12x-6x^2=0

Divide by the value of a (-6)

9/6-2x+x^2

Reorder

x^2-2x+9/6

Complete the square. Get a new value of c using (b/2)^2

x^2-2x=-9/6

new value of c=1, add to both sides

x^2-2x+1=-9/6+1

x^2-2x+1=-1/2

Factor the trinomial

(x-1)^2=-1/2

Answer 2

Oh I see thank you!

Answer 3

Let's first transpose the equation into
-6x^2 + 12x -9 = 0

To complete the square http://www.1728.org/quadr2.htm
Move non-x term to the right
-6x^2 + 12x = +9

Divide the equation by the coefficient of x^2
x^2 -2x = -1.5

take the coefficient of x
divide it by 2
square it
add it to both sides of the equation

coefficient of x is -2
divided by 2 is -1
-1 squared is +1 so

x^2 -2x +1= -.5

Answer 4

(x-1)*(x-1) = -.5
which is what dtan5457 calculated
great minds think alike!

Answer 5

Hahaha thanks wolf.