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(2x^) (3x^1/2) A)6x^13/2 B)6x^3 C)5x^13//2 D)5x^3 @Luiqi0210
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@Luigi0210
What's the first one? 2x^ ?
2x^6
For this one, just add the exponents like so: \(\Large (2*3)x^{6+1/2} \) Should give you something like \(\Large 6x ^ {13/2}\)
6 will be 12/2, just add it to 1/2 resulting in the 13/2.
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If you have exponents like \(\Large (x^a)^b then that'll be a case where you multiply instead of add.
*\(\Large (x^a)^b \)
Thank u
You're welcome :)
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