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OpenStudy (anonymous):
(PLEASE HELP, I seem to lose a step or something since I get confused in some parts) A ball is thrown upward with an initial velocity of 48 ft/s from a height 864 ft. h=-16t^2+48t+864 After how many seconds will the ball reach the ground? (i.e For what positive value of t is h=0?)
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ganeshie8 (ganeshie8):
\[0=-16t^2+48t+864\] solve \(t\)
OpenStudy (anonymous):
didn't help much.
OpenStudy (anonymous):
divide both side by -16
OpenStudy (anonymous):
Dude thank you!
OpenStudy (anonymous):
figure it out?
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OpenStudy (anonymous):
Yeah I got it correct thanks man
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