please help
http://gyazo.com/2c63f8966aacdf847693d01eee684247 help please @mathstudent55
what dont you get?
x=4
first off how much bigger is the first polygon?
ok
so take similar sides and divide them by eachother and you get what?
There are 3 pairs of corresponding sides with lengths. x - 3 corresponds to 2.5 8 corresponds to 2 16 corresponds to 4
The sides x - 3 and 2.5 have an expression x - 3, so you can't tell how much larger the left polygons is than the right polygon. Now look at the sides 8 and 2, or the sides 16 and 4. How many times larger is the the left side than the right side.
can u help with other one
How about finishing this one first?
ok
2
How many times larger is the side of the left polygon than the corresponding side of the right polygon? 8 and 2 16 and 4
It's not 2. 2 times 4 is not 16
8
You still don't understand it, so let me start from the beginning. Here are the two pentagons. One pair of corresponding sides is shown. |dw:1423071000384:dw|
Since that pair of corresponding sides shows x - 3 and 2.5 as the lengths, and we don't know what x is equal to yet, we don't know how many times the second pentagon is smaller than the first one. We need more information.
|dw:1423071171466:dw|
The figure above shows two more pairs of corresponding sides with their lengths given. The length 16 corresponds to the length 4. The length 8 corresponds to the length 2.
|dw:1423071259486:dw|
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