Question

I really need help understanding this!! :( WILL MEDAL. What is the area of a regular hexagon with a side length of 10 meters and a distance from the center to a vertex of 10 meters?
http://www.thelearningodyssey.com/Assess/DPT/QIEImagesStorage/AQ13G/AQ13GE_GE726_02_stem1_1.jpg
A) 519.6m squared
B) 259.8m squared
C)77.0m squared
D) 8.7m squared

Answer 1

I know I need to find the Apothem, but I can't seem to do it correctly. :,(

Answer 2

@hartnn

Answer 3

@ganeshie8

Answer 4

Anyone? :,(

Answer 5

Area = (½)nsr

Answer 6

A regular hexagon is made up of 6 isosceles triangles:


Area of a triangle = base * height/2

Answer 7

area= 1/2 * 6 (s) * h
finding h using hyp^2=adj^2+opp^2
h=opp, r=hyp, r=adj/2
100=25+h^2
h=sqrt(75)=5sqrt(3)
the area = 1/2*6*10*5 sqrt(3)=150sqrt(3)=259.8

Answer 8

@McNood ! A regular hexagon is made up of 6 isosceles triangles:

- why just isosceles triangles ? do you can explain me please ?

Answer 9

@MrNood the center angles what measure has ?

Answer 10

when you say hexagon so this not mean six parts of 360 degree ?
so 360/6=60

yes ?

Answer 11

so than you know that the center angle of a triangle has 60 degree and the lateral sides are equales because are radius than you consider this hexagon inside of a circle so this mean that the second and the 3rd angles are equales qhat mean that are the same 60 degree measure

so this mean that these triangles are not just isoscele so there are equilaterale

ok ?

Answer 12

sorry - I misread and thought the 10m was height of triangle - not side

YES indeed the triangles ARE equilateral as well as isosceles

all the formulae and answer have already been posted