Question

what is the solution to the equation
-6z + 1 = 13
a. z = -6
b. z = -2
c. z = 2
d. z = 6

Answer 1

Hello @taylorsuzanne505 and Welcome to OpenStudy! :)

to solve for z in this equation, we want to get z alone
so first try subtracting 1 from both sides
-6z + 1 = 13
-1 -1
------------
what would you get? :)

Answer 2

im confused already, sorry. what exact number am i subtracting from? 13 & 1?

Answer 3

@sleepyhead314

Answer 4

yes, 13 and 1
1 - 1 = 0
and 13 - 1 = 12

so you can get
-6z + 1 = 13
-1 -1
------------
-6z = 12 do you see that? :)

Answer 5

okay, so. z would be -6?

Answer 6

not quite :)

from -6z = 12 we should divide both sides by -6
/-6 /-6
so z = 12 divided by -6 = ?

Answer 7

Z = -2

Answer 8

that's what I got :)

Answer 9

can you help with a few more? these kind of problems confuse me.

Answer 10

of course :)

Answer 11

okay one sec. let me post it.

Answer 12

If 4 + 8a = 4, what is the value of a.
a. -8
b. -1
c. 0
d. 1

Answer 13

try subtracting 4 from both sides first :)

Answer 14

4 - 4 = 0
8 - 4 = 4

Answer 15

not quite, it's more like
4 + 8a = 4
-4 -4
-----------
8a = 0

Answer 16

i see now

Answer 17

so its 0?

Answer 18

yep :)

Answer 19

sorry but I gtg now
you can close this question and ask a new one if you have any more questions and someone else will be able to come and help you :)