Help me with this? MEDAL AND FANNNNN!
y-y1=m(x-x1) r u familiar with that eqn? ^^
no, i don't think so (I'm dumb sorry)
lol it's okay but that's the point-slope form y1 is 3 and x1 is 2 in this case (b/c they gave us (2,3) m is slope
let's find slope do u see any point where it perfectly meets like (0,2) ? @piercetheveil47
-1, 0
is that correct?
u mean 0,-1 :P
oops sorry LOL i knew i had to flip those
hello? @Godlovesme
hey :) so how many ups and overs do u have to go to get from (2,0) to (0,-1) ?
you have to go like 2 or 1/2? I'm just really confused like idk :(
u r right 1/2 but it's two to the right and one down so the down makes the 1/2 negative :)
So the answer will be C?
lemme check 1sec
okay :)
not really :( y-3= -1/2( x-2) y-3= -1/2x +1
y-3+3 = -1/2x +1+3 y=-1/2x +4 :)
ohhh okay!!!! Thank you! i understand
u r welcome, as always =))
The easiest way is to look at the graph and come up with two linear equations and solve for the variable. From the graph you provided lets call point A = (-2,0) and point B = (0,-1). Using the equation in y intercept form y =mx + b.Now we can just plug in the points from the graph. 0 =-2m +b -1= b Plug in b into the first equation. b/2=m m= -1/2 Now we know the slope. Normally we would find b but the point (2,3) will not pass through the line. So we need point (2,3). From the equation we found y =-1/2x+ b. Now we can plug in points to find b. 3 = -(1/2)(2) + b 3= -1 +b 4 = b y= -1/2x + 4 is the final solution.
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