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Mathematics 21 Online
OpenStudy (help!!!!):

Help me write this polynomial as the product of two binomials 3(a-1)squared+2(1-a)

OpenStudy (danjs):

This? \[3*(a-1)^2+2*(1-a)\]

OpenStudy (daniellelovee):

I think so

OpenStudy (danjs):

Expand everything first. ..

OpenStudy (daniellelovee):

so distributive property

OpenStudy (daniellelovee):

lol you always confuse me with the asker

OpenStudy (daniellelovee):

whoever asked this question is now offline

OpenStudy (danjs):

\[3(a^2-2a+1) + 2 - 2a\] \[3a^2-6a+3+3-2a\]

OpenStudy (danjs):

oh. haha

OpenStudy (danjs):

Might as well finish the thing...

OpenStudy (daniellelovee):

sure just dont give out the answer or someone will report you (that someone won't be me though)

OpenStudy (danjs):

mistyped a 3 instead of a 2 above... it evaluates to \[3a^2-8a+5\]

OpenStudy (danjs):

Factor that into something like \[(c \pm b)*(d \pm e)\]

OpenStudy (daniellelovee):

great job! lol you got a medal

OpenStudy (danjs):

:-O yayyy

OpenStudy (help!!!!):

\[3\left(a-1\right)^2+2\left(1-a\right)\]

OpenStudy (daniellelovee):

haha apparently I'm very bored :)

OpenStudy (help!!!!):

Sorry guys computer lagged out. That is the equation

OpenStudy (danjs):

k, read above, i had the right one. All you have to do now after expanding that and simplifying it to ... \[3a^2-8a+5\] is factor it

OpenStudy (help!!!!):

so im trying to get this polymonial to two binomials

OpenStudy (help!!!!):

isnt there another way to solve this besides distributing? @DanJS

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