Question

x^3-14x=0
How many rational solutions?
How many irrational solutions?

Answer 1

@Directrix @jim_thompson5910 @robtobey Help please1 :)

Answer 2

hey!!

Answer 3

this has to factor right? since there is a common factor of \(x\) in both terms !

Answer 4

Hi !

Answer 5

Your right

Answer 6

once you write \[x(x^2-14)=0\] it should be easy to solve (easy enuf)

Answer 7

I got 3 answers

Answer 8

yes, you should
\[\{0,\sqrt{14},-\sqrt{14}\}\]

Answer 9

There should be three though right because the leading coefficient had an exponent of 3

Answer 10

Yup thats what i got

Answer 11

How many are rational and how many are irrational?

Answer 12

@misty1212

Answer 13

0 is rational for sure right?

Answer 14

and since \(14\) is NOT a perfect square, then \(\sqrt{14}\) is irrational

Answer 15

Okay so 1 rational and 2 irrational

Answer 16

yup

Answer 17

Thank you so much !

Answer 18

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