3(a-1)square + 2(1-a) Could you show me the steps? I know the answer but I'm confused by a certain method to answer this problem without using distribution
\[3\left(a-1\right)^2+2\left(1-a\right)\]
Thought i did this exact prob already
you did but there's another method to solve this..
by expanding the problem
and not using distribution
you cant solve this problem, just simplify or change the form
take a (a-1) out of the first term, then take -1 out of the second term
\[3*(a-1)(a-1)-2(a-1)\]
now factor out (a-1) form both terms
You are still going to have to distribute a little bit
ohhhh okey
\[(a-1)*[3(a-1)-2]\]
I found out my mistake
still need to distribute that 3(a-1)
(a-1)(3a-5)
yeah, thats the same answer as before, from expanding the entire thing, then factoring
Thanks for the help
welcome
Join our real-time social learning platform and learn together with your friends!