3(a-1)square + 2(1-a)
Could you show me the steps? I know the answer but I'm confused by a certain method to answer this problem without using distribution
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OpenStudy (help!!!!):
\[3\left(a-1\right)^2+2\left(1-a\right)\]
OpenStudy (danjs):
Thought i did this exact prob already
OpenStudy (help!!!!):
you did but there's another method to solve this..
OpenStudy (help!!!!):
by expanding the problem
OpenStudy (help!!!!):
and not using distribution
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OpenStudy (danjs):
you cant solve this problem, just simplify or change the form
OpenStudy (danjs):
take a (a-1) out of the first term, then take -1 out of the second term
OpenStudy (danjs):
\[3*(a-1)(a-1)-2(a-1)\]
OpenStudy (danjs):
now factor out (a-1) form both terms
OpenStudy (danjs):
You are still going to have to distribute a little bit
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OpenStudy (help!!!!):
ohhhh okey
OpenStudy (danjs):
\[(a-1)*[3(a-1)-2]\]
OpenStudy (help!!!!):
I found out my mistake
OpenStudy (danjs):
still need to distribute that 3(a-1)
OpenStudy (help!!!!):
(a-1)(3a-5)
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OpenStudy (danjs):
yeah, thats the same answer as before, from expanding the entire thing, then factoring