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Choose the slope-intercept equation of the line that passes through the point (2, -3) and is perpendicular to y = 2/3x + 3
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a. y = -three halvesx b. y = three halvesx - 6 c. y = -two thirdsx - 5 thirds d. y = two thirdsx - 13 thirds
perpendicular to the line y = 2/3x + 3, means with a slope of -3/2.
So you have the point (2,-3) mand the slope (-3/2).
\[y-y_1=\left(x-x_1\right)\]
lol good thing mathematicians invented fraction notation so you can write \(\frac{3}{2}\) etc
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I don't have my latex thing with me right now
A
yes
Ok thanks I get it now
:)
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