Question

help

Answer 1

\[\frac{ x(3x+3)}{ x(4x+4) }=\frac{ 3x+3 }{4x+4 }\]

Answer 2

how are these equivalent?

Answer 3

@hartnn

Answer 4

x * 3x = ??

Answer 5

just cancel out x from the numerator and denominator
(and note that x cannot be =0 now)

Answer 6

\[3x \times x = 3x^2\]

Answer 7

is that how it works though?

Answer 8

3x * x = x^2 is correct
and yes

Answer 9

**3x^2

Answer 10

so then.

Answer 11

\[\frac{ x(3x+3) }{ x(4x+4) } = \frac{ 3x^2 + 3 }{ 4x^2 + 4 }\]

Answer 12

? is that correct?

Answer 13

no
x will be distributed to 3 too

Answer 14

really? but they aren't like terms.

Answer 15

a(b+c) = ab + ac

Answer 16

so then

Answer 17

unlike terms cannot be Added or subtracted
but they can be multiplied

Answer 18

\[\frac{ x(3x+3) }{ x(4x+4) }=\frac{ 3x^2+3x }{ 4x^2+4x }\]

Answer 19

i see. so is this correct?

Answer 20

@hartnn

Answer 21

yes, but why are you doing all that?

why won't you just cancel out x from numerator and denominator?

Answer 22

because i want to understand how it works.

Answer 23

instead of knowing just how to get the answer lol.

Answer 24

it works only by cancelling out the x from num and denom.
thats what you should understand :P

Answer 25

wait what? are you sure?

Answer 26

yes, thats it
just cancel those damn x's
and you're done

nothing complicated

Answer 27

b-b-but i want a full understanding of how this works.

Answer 28

:(

Answer 29

thanks