Question

Given f(x) = -3x^2 + 4x, Find the following.

f(a)

f(x+1)

Answer 1

Degree = 2

Answer 2

what do you mean by that? are you asking if that (^2) is "to the second degree" ?

Answer 3

@YOLO_KING

Answer 4

Nvm I looked at the problem wrong

Answer 5

So your looking to factor it pretty much?

Answer 6

because \[f(x)=-3x^2+4x\]

Answer 7

Not sure ,

f(a) = -3a^2 + 4 a
f(x+1) = -3(x+1)^2 + 4(x+1) = -3(x^2 + 1 + 2x) + 4x + 4
= -3x^2 - 3 - 6x +4x + 4
-3x^2 - 2 x + 1 = f(x+1)

Answer 8

OOps i meant \[f(x) = -x(3x-4)\]

Answer 9

Well the given part is f(x)=−3x2+4x
on f(a) i got 3a^2 + 4(a) but i think theres another step

Answer 10

@YOLO_KING @TrojanPoem

Answer 11

you can do :
f(a) = a(3a + 4)

Answer 12

Given f(x) = -3x^2 + 4x, Find the following. f(a) f(x+1)
to find f(a) replace x with a and rewrite to get f(a) = -3a^2 + 4a = a(4 - 3a)
to find f(x + 1) replace x in f(x) with (x + 1 ) then simplify
f(x + 1) = -3(x + 1)^2 + 4(x + 1) = (x +1)( 4 - 3(x + 1))
= (x + 1)(4 - 3x -3)= (x + 1)(1 - 3x)

if you look closely you will see that after writing f(a) = a(4 - 3a) to find f(x + 1) you can let a = x + 1 and do the substitution