Question

Show that:

Answer 1

\[\ln (1+e ^{2x})=2x+\ln(1+e ^{-2x})\]

Answer 2

@Nnesha @dan815

Answer 3

@ganeshie8

Answer 4

Do you need to solve for X?

Answer 5

@Andrew12840

Answer 6

no prove it

Answer 7

please note that:
\[\begin{gathered}
\ln \left( {1 + {e^{ - 2x}}} \right) = \ln \left( {1 + \frac{1}{{{e^{2x}}}}} \right) = \hfill \\
= \ln \left( {\frac{{1 + {e^{2x}}}}{{{e^{2x}}}}} \right) \hfill \\
\end{gathered} \]