5x=2y-7 find the x and y intercept
You can always find \(x\)-intercept by putting \(y=0\).. So, put y = 0, and find x..
And when you again will put x = 0 and find y, that will be your y-intercept...
5/7?
Put y = 0, and show me what you got..
x=5/7 y=?
How?? I said just put y = 0, and show me, don't solve it further..
5x=-7
See, here you have : \(5x = 2y - 7\) Put \(y=0\), \(5x = 2(0) - 7\) \(\implies 5x = -7\) Find \(x\) now..
If found x, then in the same way, do it again but at that time, put x = 0 and find y, that will be your y-intercept..
x=-5/7
No..
This is the basic concept dear, you are solving the next part before learning the previous part.. This is dangerous..
\[5x = -7\] Divide by \(5\) both the sides and tell me what will you get?
-7/5
It is good...
Similarly when we put : \(x=0\), \(5x = 2y - 7\) \(\implies 0 = 2y - 7\)
7/2
Good..
thank you
\[x-intercept : (\frac{-7}{5},0) \\ y-intercept : (0, \frac{7}{2})\]
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