Question

Can someone help me and explain it to me please!!!
4m^2+3m=1 quadratic formula

Answer 1

4m^2+3m-1=0 is the in the form am^2+bm+c. where a=4, b=3 and c=-1. now use the quadratic formula \[m=-b+-\sqrt{b^2-4ac}/2a\] plugging in a,b and c.

Answer 2

ok thank u so much

Answer 3

is that going to be 25?

Answer 4

The -b is also divided by 2a.
\[m = \frac{ -b \pm \sqrt{b^2-4*a*c} }{ 2a }\]

Answer 5

Doing a quick factoring...

4m^2 + 3m - 1
=
(m+1)*(4m-1) = 0

(m+1) = 0
or
(4m-1)=0

The two values for m from the quadratic formula should come out to , m=-1 or m=1/4, if you did the math correctly.