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Mathematics
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Trig. Sub?
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\[\int\limits_{}^{} \frac{ \sqrt{x^2-9}}{ x} dx\]
you're trying \(\Large x = 3 \sec u\) ? worth a shot
Here's what I tried to do \[x^2-9=9sec^{2}\theta-9=9tan^{2}\theta\]
\(x=3sec^{2}\theta\)
not sec^2 you've tried x= 3 sec thetha
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\[\int\limits_{}^{}\frac{ \sqrt{9\tan^{2}\theta} }{ 3\tan\theta }*3\sec^{2}\theta~dx\]
Oh my bad, i meant \(x=3sec\theta\)
so denominator would be 2 sec thetha, roight ?
*3 sec thetha**
Oh, makes sense ! >.< THanks @hartnn this mistake was small but ughhhh
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also be careful with your derivatives :)
Yes! :)
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