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Mathematics 10 Online
OpenStudy (anonymous):

What is the third quartile of the following data set? 24, 20, 35, 39, 28, 42, 25, 29, 44, 21, 37 A. 39 B. 35 C. 29 D. 37

OpenStudy (anonymous):

@Mehek14 Is it the same thing as last time? where you put them in order from least to greatest?

Mehek (mehek14):

yes that is how you get the second quartile

OpenStudy (anonymous):

So then how do I find the 3rd quartile?

OpenStudy (acxbox22):

put them in order find the median separating the 1st quartile and third quartile

Mehek (mehek14):

well first find the second then find the median of the numbers that come after that

Mehek (mehek14):

that is how you get the third

OpenStudy (anonymous):

the second one or 2nd quartile is the median right?

Mehek (mehek14):

yes of all the numbers

OpenStudy (anonymous):

the 2nd one is 29

Mehek (mehek14):

hold on let me check

OpenStudy (anonymous):

ok

OpenStudy (acxbox22):

first put all the numbers in order and tell me what is the median of the set

Mehek (mehek14):

ok 29 is correct

Mehek (mehek14):

now find the median of the numbers that come after 29

OpenStudy (anonymous):

so rewrite it without 29?

Mehek (mehek14):

yes you don't need 29

Mehek (mehek14):

but remember you aren't going to put all the numbers only the numbers that come after 29

OpenStudy (anonymous):

35,37,39,42,44 Median 39

Mehek (mehek14):

there you go :)

OpenStudy (anonymous):

so the answer would be 39

Mehek (mehek14):

yup

OpenStudy (anonymous):

If there are 25 values in a data set in order from smallest to largest, what is the first quartile of the data set? A. The mean of the 7th and 8th values B. The mean of the 6th and 7th values C. The mean of the 4th and 5th values D. The mean of the 5th and 6th values can you help me with this one then i'll close the question..

Mehek (mehek14):

ok

Mehek (mehek14):

write down all the number 1-25

OpenStudy (anonymous):

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25

Mehek (mehek14):

ok find the median

OpenStudy (anonymous):

13.5?

Mehek (mehek14):

ok

Mehek (mehek14):

now find the median of 1-12

OpenStudy (anonymous):

6

Mehek (mehek14):

no

Mehek (mehek14):

it is between 2 numbers

OpenStudy (anonymous):

6.5

Mehek (mehek14):

yes so between which 2 numbers

OpenStudy (anonymous):

6 and 7

Mehek (mehek14):

yea so that's the answer

OpenStudy (anonymous):

Thanks for the help

Mehek (mehek14):

ur welcome ^_^

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