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Algebra 14 Online
OpenStudy (anonymous):

I'm a freshman in Algebra 1. If anyone could help me I would super greatfull!

OpenStudy (anonymous):

I'm working on substitution. X= 3-2y and 2X+4y=6

OpenStudy (sleepyjess):

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OpenStudy (sleepyjess):

ah, substitution :) So, we need to solve for y first since we are given what x is. Do you know how to substitute the first expression into the second?

OpenStudy (anonymous):

I'm not sure how to start it! I understand the substitution part its just getting it set up I don't know!

OpenStudy (sleepyjess):

That is ok :) we are given that x = 3 - 2y, and 2x + 4y = 6. So since we know the value of x, 3 - 2y, we can substitute that into the second expression giving us only y. 2(3 - 2y) + 4y = 6

OpenStudy (sleepyjess):

Hmmmmm... this is not coming out correctly in my mind...

OpenStudy (anonymous):

wow! I actually started that right on my paper! then I distributed the parenthesis numbers and got 6-4y+4y=6

OpenStudy (sleepyjess):

yeah, which leaves us 6 = 6, we should end up with y = something I will be right back

OpenStudy (anonymous):

ok thank you:)

OpenStudy (sleepyjess):

ok, I'm back

OpenStudy (anonymous):

ok how did you get 6=6

OpenStudy (sleepyjess):

What is -4y + 4y?

OpenStudy (anonymous):

um i don't know

OpenStudy (sleepyjess):

what is -4+4?

OpenStudy (anonymous):

-8y ?

OpenStudy (sleepyjess):

maybe this will be clearer, what is 4-4?

OpenStudy (anonymous):

0

OpenStudy (sleepyjess):

yep, so 4y-4y is 0y, which is 0

OpenStudy (anonymous):

okay!

OpenStudy (anonymous):

i ended up getting y=3

OpenStudy (sleepyjess):

How though?

OpenStudy (anonymous):

iafter i distributed it got 6-4y+4y=6 then I added the 4y's but since its negative i need to subtract

OpenStudy (sleepyjess):

mhmm, after we cancel out the y's, all that is left is 6=6

OpenStudy (anonymous):

so i got 6=6

OpenStudy (sleepyjess):

@phi

OpenStudy (sleepyjess):

He may be able to help/clarify.

OpenStudy (anonymous):

what do we do after 6=6

OpenStudy (anonymous):

youre actually helping me

OpenStudy (sleepyjess):

I am really not sure what to do... ;/

OpenStudy (anonymous):

hmm me either

OpenStudy (sleepyjess):

@ganeshie8

OpenStudy (sleepyjess):

Unless this system of equations is unsolvable....

ganeshie8 (ganeshie8):

\[6=6\] is always true, so we have infinitely many soltions

OpenStudy (sleepyjess):

aaaahhhhh

OpenStudy (sleepyjess):

yep, if you put them into the same form, they are the same line

OpenStudy (anonymous):

okay, so that's all we can do?

ganeshie8 (ganeshie8):

Exactly! yes thats it

OpenStudy (anonymous):

the answer is 6=6 infinite solutions

ganeshie8 (ganeshie8):

6=6 is always true so infinite solutions

OpenStudy (anonymous):

thanks guys! :) you helped a lot!

OpenStudy (sleepyjess):

No problem! and thank you @ganeshie8 for clarifying :)

OpenStudy (anonymous):

yes :)

OpenStudy (sleepyjess):

If you have any questions about the site, feel free to ask me :)

OpenStudy (anonymous):

thanks! I just started it and it's really great!

OpenStudy (sleepyjess):

You can click "Best response" on the right to give the person you feel helped the most a medal.

OpenStudy (anonymous):

you both did but you helped me first!

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