I'm a freshman in Algebra 1. If anyone could help me I would super greatfull!
I'm working on substitution. X= 3-2y and 2X+4y=6
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ah, substitution :) So, we need to solve for y first since we are given what x is. Do you know how to substitute the first expression into the second?
I'm not sure how to start it! I understand the substitution part its just getting it set up I don't know!
That is ok :) we are given that x = 3 - 2y, and 2x + 4y = 6. So since we know the value of x, 3 - 2y, we can substitute that into the second expression giving us only y. 2(3 - 2y) + 4y = 6
Hmmmmm... this is not coming out correctly in my mind...
wow! I actually started that right on my paper! then I distributed the parenthesis numbers and got 6-4y+4y=6
yeah, which leaves us 6 = 6, we should end up with y = something I will be right back
ok thank you:)
ok, I'm back
ok how did you get 6=6
What is -4y + 4y?
um i don't know
what is -4+4?
-8y ?
maybe this will be clearer, what is 4-4?
0
yep, so 4y-4y is 0y, which is 0
okay!
i ended up getting y=3
How though?
iafter i distributed it got 6-4y+4y=6 then I added the 4y's but since its negative i need to subtract
mhmm, after we cancel out the y's, all that is left is 6=6
so i got 6=6
@phi
He may be able to help/clarify.
what do we do after 6=6
youre actually helping me
I am really not sure what to do... ;/
hmm me either
@ganeshie8
Unless this system of equations is unsolvable....
\[6=6\] is always true, so we have infinitely many soltions
aaaahhhhh
yep, if you put them into the same form, they are the same line
okay, so that's all we can do?
Exactly! yes thats it
the answer is 6=6 infinite solutions
6=6 is always true so infinite solutions
thanks guys! :) you helped a lot!
No problem! and thank you @ganeshie8 for clarifying :)
yes :)
If you have any questions about the site, feel free to ask me :)
thanks! I just started it and it's really great!
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you both did but you helped me first!
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