Question

A system of equations is given below.

Answer 1

@Daniellelovee

Answer 2

@Legends

Answer 3

Sorry I don't undersand this one.

Answer 4

i never do xD

Answer 5

know anyone?

Answer 6

@hysusonic

Answer 7

@Directrix

Answer 8

@ilovewolf

Answer 9

For part one, multiply the first equation (all terms of it) by 3 and post what you get.

Answer 10

6x+21y=3

Answer 11

@Directrix

Answer 12

That is good for part one.

Answer 13

Part Two: Solve the new system:

6x + 21y = 3
-3x - 4y = 5
---------------------

Answer 14

Suggestion: Multiply every member of the second equation by 2.

Post what you get.

Answer 15

-6x-8y=10 @Directrix

Answer 16

Okay.

The system is now ready to be solved. Add like terms and post what you get.

6x + 21y = 3
-6x - 8y = 10
---------------

Answer 17

do i add up and down or within the one system?

Answer 18

is this all for A? @Directrix

Answer 19

Add like terms. We are currently on part two. Look at the question.

Answer 20

>>do i add up and down or within the one system?

I don't know what you are asking.

Those two equations form a system.

Add the like terms so that you can solve for y.

Answer 21

I mean like -6x+6x @Directrix

Answer 22

Yes

6x + 21y = 3
-6x - 8y = 10
-------------
0 +

Keep going.

Answer 23

0+13=13

Answer 24

@Directrix

Answer 25

Do 21y - 8y first.

Yes, 0 + 13 = 13

Answer 26

:D ok so thats a now what about b and c ??

Answer 27

Use any method to solve the equivalent system of equations (the new first equation with the original second equation).
Prove that the solution for the equivalent system is the same as the solution for the original system of equations.

because i don't i swear i don't understand what they even mean

Answer 28

We are still in the middle of part B

6x + 21y = 3
-6x - 8y = 10
-------------
13y = 13

Solve for y.

If 13*y = 13, then what is the value of y? @Sparklestaraa

Divide by sides of 13*y = 13 by 13 to get y = ?

Answer 29

13/13=1 so y=1 ??? @Directrix

Answer 30

i think its supposed to be the new 1st equation with the original second equation at least thats what it says.

Answer 31

Now, solve for x.

-6x - 8y = 10

-6x - 8(1) = 10

Solve that for x.

Then, part B ends.

Part C is to solve the two old equations using the same method.

We are supposed to get the same common solution on Part C that we get on Part B.

Answer 32

so i divide what here?

Answer 33

is it 0?

Answer 34

or -1

Answer 35

@Directrix

Answer 36

-6x - 8(1) = 10

-6x - 8 = 10

Add 8 to both sides of the equation

Answer 37

2 and 18

Answer 38

@Directrix

Answer 39

-6x - 8 = 10

-6x = 18

x = -3

Answer 40

The solution to Part B is the order pair (-3, 1)

Now, to part C.

Answer 41

kk :D

Answer 42

Solve the original system:

2x + 7y = 1
-3x - 4y = 5
-------------

your task: Multiply every member of this equation by 4: 2x + 7y = 1

Answer 43

I'm down this far- 2x +7y=1
-3x-4y=5

2*4= 8 7*4=28 1*7=7

-3*7= -21 4*4=16 5*4= 20

8x+28y=7
-21x-16y=20
__________
-13x+44y=27
@Directrix

Answer 44

>>8x+28y=7 should be 8x + 28 y = 4

Answer 45

8x + 28 y = 4
-3x - 4y = 5 ------> Your task: multiply every member of this equation by 7

Answer 46

@Sparklestaraa

Answer 47

I'm here sorry let me read

Answer 48

I'm confused how did u get to 4? and what???

Answer 49

your task: Multiply every member of this equation by 4: 2x + 7y = 1

4 times the 1 on the end = 4

Answer 50

8x + 28y = 4
-21x - 28y = 35
-------------------
-13x = 39
x = -3

Answer 51

To get y, take the equation 2x + 7y = 1
In place of x, substitute x = -3

2 * (-3) + 7y = 1
-6 + 7y = 1
7y = 7
y = 1

Answer 52

Solution to original set of equations in Part A is ( -3, 1).

That is the same as the solution to the new equations in Part B.

So, the two systems of equations are equivalent.

Problem complete.

Answer 53

THANKS SO SO SO MUCH :D :D UR THE BESTTTT :D @Directrix