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is 3r(4x^2-9) completely factored?
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yes.
thank you!
no problem... it is 3r right not 3x?
yep
it is 3r
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Actually, no, it's not completely factored.
okay well you gotta explain this because now im confused..
\((4x^2-9) \) can be factored still.
oh so would it be (2x-3) ?
so it 3r(2x+3)(2x-3)
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Yes @jpes2193 @jessieboxador2319 if it was \((2x-3)^2 \) it would end up as \( 4x^2 -12x+9\) :)
thanks for catching that mistake... greatly appreciated :)
You're welcome :P
Thanks guys!
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