Question

What is the slope-intercept form of the function that contains the points (6, 2) and (4, 8)?

Answer 1

First we find the slope:

\(m = \dfrac{y_2-y_1}{x_2-x_1}\)

\(m = \dfrac{8-2}{4-6}\)

Subtract & then divide

Answer 2

6/-2

Answer 3

=2/6

Answer 4

y=mx+b

Answer 5

@iGreen.

Answer 6

Yes, what's 6 / -2?

Answer 7

-3

Answer 8

am i right @iGreen.

Answer 9

Yes, so the slope is -3, now let's plug this in with another point in point-slope form.

\(y - y_1 = m(x - x_1)\)

Where \(y_1\) is the y-value of the point, \(x_1\) is the x-value of the point, and \(m\) is the slope.

So we have:

\(y - 2 = -3(x - 6)\)

Distribute -3 into the parenthesis:

\(y - 2 = -3x + 18\)

Now add 2 to both sides, what's 18 + 2?

Answer 10

20