The length of a rectangle is 5/6 ft. The width is 3/8 ft. How much greater is the length of the rectangle than the width? Express your answer in lowest terms.
Divide both the lengths.
\[\large \frac{\frac{5}{6}}{\frac{3}{8}} = ??\]
5sos?
20/9
@waterineyes We don't divide fractions, we multiply.. \(\dfrac{5}{6} \div \dfrac{3}{8} = \dfrac{5}{6} \times \dfrac{8}{3}\) We flip the 2nd fraction and multiply. \(\dfrac{5}{6} \times \dfrac{8}{3} \rightarrow \dfrac{5 \times 8}{6 \times 3}\) Multiply 5 * 8 and 6 * 3
5*8=40 and 6*3=18
You are multiplying the reverse of other fraction..
\[\frac{ 5 }{ 6 }-\frac{ 3 }{ 8 }=\frac{ 20-9 }{ 24 }=\frac{ 11 }{ 24 }\]
5/6 = 0.83 3/8 = 0.37 Now divide.. :P
so 11/24 is the answer???
And yes, we divide fractions by the process of multiplication as you have shown. :P
who do i give the medal 2?
To surjit..
WAIT I HAVE ANOTHER QUESTION LAST ONE
I still think 20/9, should be correct..
20/9 means two times rouphly is length twice the breadth?
Yes, so we have 40/18..
it is simply subtract width from length.
if the question is how many times the length to width then divide. if how much greater the length to width, then subtract.
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