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OpenStudy (anonymous):
What is the slope-intercept form of the function described by this table?
x 1 2 3 4
y 2 7 12 17
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Mehek (mehek14):
subtract y2-y1/x2-x1
Mehek (mehek14):
choose any two points
OpenStudy (anonymous):
1- 1/5x+b
Mehek (mehek14):
?
OpenStudy (anonymous):
m=y2-y1
x2-x1 right
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Mehek (mehek14):
yes so choose 2 points
OpenStudy (anonymous):
m=2/7-1/2=1/5
Mehek (mehek14):
it would be the other way
7/2-2/1 = 5/1
because y has to be on top and x on the bottom
OpenStudy (anonymous):
O So What Do I Do Now
OpenStudy (anonymous):
@Mehek14
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Mehek (mehek14):
so your slope is 5
y = 5x + b
now we have to find b
substitute the value of any points
Mehek (mehek14):
can you do that?
OpenStudy (anonymous):
1-1/5=1/5- 1/5+b
Mehek (mehek14):
no not like that
Mehek (mehek14):
lets use 1,2
so since 2 is y and 1 is x,
2 = 1x + b
now solve that
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OpenStudy (anonymous):
1-1/2=1/2-1/2+b
Mehek (mehek14):
how do get that???
OpenStudy (anonymous):
i dont get what you have to do tbh
Mehek (mehek14):
|dw:1423518323270:dw|
Mehek (mehek14):
im using points 1,2
1 is x so substitute that for x and 2 is y so substitute that for y
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OpenStudy (anonymous):
so thats the answer
Mehek (mehek14):
yes the equation
Mehek (mehek14):
do you get it?
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