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write the sum of the series as a function of x http://puu.sh/fIufn/893b76b113.png
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you want a guess i would say \(e^{-3x}\)
how?
bad guess nvm
without the \(3n\) i.e .with just \(n\) it would be \(e^{-x}\)
lol i am an idiot
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law of exponents, try \[e^{-x^2}\]
make that \[e^{-x^3}\]
starting with knowing that \[e^x=\sum\frac{x^n}{n!}\]so \[e^{-x}=\sum\frac{(-x)^n}{n!}\]
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